I know this is after quite a while. But I looked into the above example and I have a question.

In the following piece of code "Convert(Object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)",

I want to know how the converter is able to receive KeyValuePair<int, Test> object in the parameter "value" when param == "Name".

I am declaring the fields in fieldLayout dynamically in code and not able to simulate it.

Appreciate the help. :) 

I thought some more information can help here. I am actually declaring my fields in code as follows.

IValueConverter conv = new MyConverter();

myGrid.FieldLayoutSettings.AutoGenerateFields = false;
FieldLayout fl = new FieldLayout();
Field f = new Field("Key");
fl.Fields.Add(f);
f = new Field()
{
Label = "Name",
BindingType = BindingType.Unbound,
Converter = conv,
ConverterParameter = "Name"
};
fl.Fields.Add(f);

myGrid.FieldLayouts.Clear();
myGrid.FieldLayouts.Add(fl);

When I try to run the program, it fails in the converter. The "value" parameter of the converter shows up null.

Hello Viswanath,

You need to set the binding on the unbound field, for example:

UnboundField NameField = new UnboundField();

        NameField.Label = "Name";

        MyConverter conv = new MyConverter();

        Binding binding = new Binding();

        binding.Converter = conv;

        binding.ConverterParameter = "Name";

        NameField.Binding = binding;

Sincerely,

Valerie

Software Developer

Infragistics Inc

Hi Valerie,

Thank you for the response. The suggested method works. But, I am getting the following alert when I try to use UnboundField.

Unbound field is obsolete: Use Field (or one of its editor specific derived classes) with the new BindingType property set to 'Unbound' or 'UseAlternateBinding' instead. The new 'AlternateBinding' and 'AlternateBindingRetentionMode' properties replace all the UnboundFields 'Binding...' properties.

Can you also tell me, how to define the third column in the example (the one with lists in each cell) programmatically?

Hello Viswanath,

Since in this case we are re-templating the CellValuePresenter and need to create a control template the best method to do this is to create the CellValuePresenterStyle in XAML and then attach it to the field in code behind. For example:

XAML:

<Window.Resources>

   <local:MyConverter x:Key="Conv"/>

   <Style x:Key="style1" TargetType="{x:Type igDP:CellValuePresenter}">

     <Setter Property="Template">

       <Setter.Value>

          <ControlTemplate TargetType="{x:Type igDP:CellValuePresenter}">

             <ListBox ItemsSource="{Binding DataItem.Value,

              Converter={StaticResource Conv},ConverterParameter=Test}" />

                    </ControlTemplate>

       </Setter.Value>

     </Setter>

    </Style>

  </Window.Resources>

C#:

UnboundField ValuesField = new UnboundField();

 Style style = (Style) this.Resources["style1"];

 FieldSettings fs = new FieldSettings();

 fs.CellValuePresenterStyle = style;

 ValuesField.Settings = fs;

Sincerely,

Valerie

Software Developer

Infragistics Inc