Hello,

I#m using XamDataGrid for WPF now for a couple of years and I must say, if you know how to do things, it's pretty awesome.

But this one I struggle:

I have grid which contains a couple of columns and the first one is unbound. Basically, I have a custom CellValuePresenterStyle and I'm showing a button for a special action on this row. That's working very good.

On the second I have a normal field and I have set IsScrollTipField = true and I get this error message:

"The Field cannot be made the 'ScrollTipField' unless it is contained in the Fields collection of the Owner."

I don't understand what it's trying to tell me? What's the issue? How to solve it?

Here for better understand my two columns as source code:

<ig:Field BindingType="Unbound" Width="18" FixedLocation="FixedToNearEdge">
    <ig:Field.CellValuePresenterStyle>
        <Style TargetType="{x:Type ig:CellValuePresenter}">
            <Setter Property="Template">
                <Setter.Value>
                    <ControlTemplate>
                        <Button Height="16" Width="16" Click="Print_Clicked" IsEnabled="{Binding DataItem.IsPrintable}">
                            <Image Source="/ISD.PRINCE;component/Images/Printer.png" />
                        </Button>
                    </ControlTemplate>
                </Setter.Value>
            </Setter>
        </Style>
    </ig:Field.CellValuePresenterStyle>
</ig:Field>
<ig:Field Name="WO" Label="{isd:Translation Key=Common.WorkOrder}" FixedLocation="FixedToNearEdge" IsScrollTipField="True"/>