Hi,
It seems like a very silly question, but is it possible to make the WebSplitter fullscreen without having to specify the exact pixel values?
I'm trying to create a screen layer with a Horizontal WebSplitter, the top pane housing menu and toolbar, and a vertical splitter to hold an outlook style web list on the left pane and main content on the right. But the WebSplitter refuses to go full screen with I set the Height to 100%.
<ig:WebSplitter ID="WebSplitter1" runat="server" Height="768px" Orientation="Horizontal" Width="100%" AutoPostBackFlags-SplitterBarPositionChanged="Off"> <panes> <ig:SplitterPane runat="server" Size="50px"> </ig:SplitterPane> <ig:SplitterPane runat="server" Size="100%"> <Template> <ig:WebSplitter ID="WebSplitter1_vert1" runat="server" Height="100%"> <Panes> <ig:SplitterPane runat="server" Size="25%"> </ig:SplitterPane> <ig:SplitterPane runat="server" Size="100%"> </ig:SplitterPane> </Panes> </ig:WebSplitter> </Template> </ig:SplitterPane> </panes> </ig:WebSplitter>
Regards,
Adrian
Hello Adrian,
Indeed, this is a tricky one. I believe it is best to take a look at the following forum thread:
http://forums.infragistics.com/forums/p/758/10469.aspx#10469
The idea is that the splitter needs a parent with position relative or explicitly set height/width in order to calculate it height in percentages correctly in Standards compliant mode. More info in the thread above.
HTH,